Netty(二):BIO

適用于較小且固定的架構 工作機制

3.連接建立后,如果當前線(xiàn)程無(wú)數據可讀,線(xiàn)程就卡在read操作上

對BIO編程流程的梳理
BIO 是傳統的java I/O編程,其相關(guān)的類(lèi)和接口在java.io

3. 客戶(hù)端發(fā)出請求后,先咨詢(xún)服務(wù)器是否有線(xiàn)程響應,如果沒(méi)有則會(huì )等待,或者被拒絕
實(shí)例 package com.zyd.bio; import java.io.InputStream; import java.net.ServerSocket; import java.net.Socket; import java.util.concurrent.ExecutorService; import java.util.concurrent.Executors; public class BIOServer { public static void main(String[] args) throws Exception { //線(xiàn)程池機制 //思路 //1. 創(chuàng )建一個(gè)線(xiàn)程池 //2. 如果有客戶(hù)端連接，就創(chuàng )建一個(gè)線(xiàn)程，與之通訊(單獨寫(xiě)一個(gè)方法) ExecutorService newCachedThreadPool = Executors.newCachedThreadPool(); //創(chuàng )建ServerSocket ServerSocket serverSocket = new ServerSocket(6666); System.out.println("服務(wù)器啟動(dòng)了"); while (true) { System.out.println("線(xiàn)程信息id = " + Thread.currentThread().getId() + "名字 = " + Thread.currentThread().getName()); //監聽(tīng)，等待客戶(hù)端連接 System.out.println("等待連接...."); final Socket socket = serverSocket.accept(); System.out.println("連接到一個(gè)客戶(hù)端"); //就創(chuàng )建一個(gè)線(xiàn)程，與之通訊(單獨寫(xiě)一個(gè)方法) newCachedThreadPool.execute(new Runnable() { public void run() {//我們重寫(xiě) //可以和客戶(hù)端通訊 handler(socket); } }); } } //編寫(xiě)一個(gè)handler方法，和客戶(hù)端通訊 public static void handler(Socket socket) { try { System.out.println("線(xiàn)程信息id = " + Thread.currentThread().getId() + "名字 = " + Thread.currentThread().getName()); byte[] bytes = new byte[1024]; //通過(guò)socket獲取輸入流 InputStream inputStream = socket.getInputStream(); //循環(huán)的讀取客戶(hù)端發(fā)送的數據 while (true) { System.out.println("線(xiàn)程信息id = " + Thread.currentThread().getId() + "名字 = " + Thread.currentThread().getName()); System.out.println("read...."); int read = inputStream.read(bytes); if (read != -1) { System.out.println(new String(bytes, 0, read));//輸出客戶(hù)端發(fā)送的數據 } else { break; } } } catch (Exception e) { e.printStackTrace(); } finally { System.out.println("關(guān)閉和client的連接"); try { socket.close(); } catch (Exception e) { e.printStackTrace(); } } } } 問(wèn)題分析